SOLUTION: Two methods of memorizing difficult material are being tested to determine if one produces better retention. A random sample of 7 pairs of students matched according to I.Q. and ac

Question 620853: Two methods of memorizing difficult material are being tested to determine if one produces better retention. A random sample of 7 pairs of students matched according to I.Q. and academic background are included in the study. Method A is randomly assigned to one student in each pair. The scores on a memorization test are listed below (by percent). Using a = .05, is there evidence to conclude a significant difference between the effectiveness of the two methods?
t � test: Paired Sample for Mean Method A Method B
Mean 61.86 65.43
Variance 70.4762 170.2857
Observations 7 7
t statistic -1.622
P-value one-tail 0.078
t Critical value one-tail 1.943
P-value two-tail 0.156
t Critical value two-tail 2.447
Is there evidence of a difference between the effectiveness of the two methods?

Answer by Cupjohn(1) (Show Source): You can put this solution on YOUR website!
This is a matched pair t -test.
So d"bar" is 61.86-65.43 = -3.57
the standard deviation is sqrt(70.4762+170.2857)=15.52
n = 7
So the t test statistic is -3.57/(15.52/sqrt(7))=-0.608591
Ho = "mu"d = 0
H1 = "mu"d is not = 0
test statistic is less than the critical values so we cannot reject the null, thus there is no evidence of a difference between the two methods
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