SOLUTION: i am working on substitutions and systems of equations. the length of a rectangle is 3 more than its width. the perimeter of the rectangle is 58 cm. what are the rectangle's dim

Question 539427: i am working on substitutions and systems of equations.
the length of a rectangle is 3 more than its width. the perimeter of the rectangle is 58 cm. what are the rectangle's dimensions?
directions: write a system of equations to represent the situation. then, solve the system by substitution.
i only need help on the coming up with the system of the equations part.
thank you!!!
p.s. i looked up the same question on the website, and i didn't get it because there were no explanations along with it. thanks!
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Recall that for a rectangle, the perimeter (P) can be expressed as:
P = 2(L+W) where L = Length and W = width.
You are given:
P = 58 "The perimeter of the rectangle is 58 cm."
L = W+3 "The length of the rectangle is 3 more than its width."
You need to start with: P = 2(L+W) and make the appropriate substitutions from the given data to solve for L and W.
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