SOLUTION: An object is projected vertically upward from the top of a building with an initial velocity of 128 ft/sec. Its distance s(t) in feet above the ground after t seconds is given by t
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Question 523986: An object is projected vertically upward from the top of a building with an initial velocity of 128 ft/sec. Its distance s(t) in feet above the ground after t seconds is given by the equation s(t) = −16t2 + 128t + 120.
A.)Find maximum distance above the ground.
B.)Find the height of the building.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Do you want the Algebra solution or the Calculus solution for part a? Either way, the height of the building is the height of the projectile at time zero. Substitute 0 for 
and do the arithmetic.
John
My calculator said it, I believe it, that settles it
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