SOLUTION: Graph the inequality on a plane:
3x+4y <= 12
Algebra.Com
Question 520222: Graph the inequality on a plane:
3x+4y <= 12
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Step 1: Change the relationship symbol to "=". Graph the resulting line. If the original relationship symbol was 
or 
, do it with a dashed or broken line. If your symbol was 
or 
, graph the equation with a solid line.
Step 2: Pick any point on the coordinate plane that does not lie on the line you just graphed. If the line does not pass through the origin, )
then the origin is an excellent choice for this step. If the line does pass through the origin, select a point other than the origin -- I recommend a point that has small integer coordinates.
Step 3: Substitute the values of the coordinates of the point chosen in Step 2 for the corresponding variables in the inequality you started with in Step 1.
Step 4: Do the appropriate arithmetic to determine whether the substitution created a true statement or not. If you created a true statement, shade in the side of the line containing the point selected in Step 2. If you created a false statement, shade in the side of the line that does not contain the selected point.
John
My calculator said it, I believe it, that settles it
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