SOLUTION: I have tried to solves these 2 problems...find two consecutive intergers such that five the first(label it as x) is ninety-seven more than three times the second. I wrote x +3x+97

Question 50733: I have tried to solves these 2 problems...find two consecutive intergers such that five the first(label it as x) is ninety-seven more than three times the second. I wrote x +3x+97.
the second problem is ..the perimeter of a rectangle is 36 feet, find the length and width if the length is 2 feet more than the width. I wrote x+2x+36
any help you can give will be appreciated..thank you
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
5X=97+3(X+1) OR 5X=97+3X+3 OR 2X=100 OR X=50
PROOF 5*50=97+(3*51) OR 250=97+153 OR 250=250
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