SOLUTION: Please help me with those problems. Thanks a lot!!! Multiplication is commutative because x*y = y *x for all x and y. Multiplication is associative because x *(y *z) = (x *y) *z.

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Question 477607: Please help me with those problems. Thanks a lot!!!
Multiplication is commutative because x*y = y *x for all x and y. Multiplication is associative
because x *(y *z) = (x *y) *z. The identity of multiplication is 1, because x*1 = x for all x.
Let a & b = a + ab + b for all a and b.
(a) Is the operation & commutative?
(b) Is the operation & associative?
(c) What number is the identity of &?
(d) What number is the inverse of 3 with respect to &? (Recall that the inverse of 3 with
respect to multiplication is 1/3 because 3 * 1/3 equals the identity of multiplication.)
Thank you very much for your help!!!! I appreciate it a lot!!!!!!! Thanks!!!

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!






Apply the commutative properties of Addition and Multiplication to the RHS of the second equation:



So, yes the operation "" is commutative

You only get one problem per post. Send me a note and I'll give you a quote for the other three problems.

John

My calculator said it, I believe it, that settles it
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