Hi,

Using the vertex form of a parabola,  where(h,k) is the vertex

f(x) =2x^2-12x+13 | Completing square to put into vertex form

f(x) = 2[(x-3)^2-9]+13

f(x) = 2(x-3)^2 - 5 |V(3,-5), a = 2 > 0, parabola opens upward, vertex a min Pt

x = 3, line of symmetry



 

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