Hi, Inanswer to Your question:  Yes, f(x) maximum value is the 6.

Using the vertex form of a parabola,  where(h,k) is the vertex

f(x) = -4(x+3)^2+6 | , a = -4<0, parabola opens downward, vertex a max Pt

x = -3, line of symmetry



 

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