SOLUTION: I'm 46 yrs old and am trying to refresh algebra. When the digits of a 2-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits

Question 459943: I'm 46 yrs old and am trying to refresh algebra.
When the digits of a 2-digit number are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?

Found 2 solutions by MathLover1, richwmiller:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

Tlet�s two -digits number be:
= the 10's digit
= units digit
The original number is:
given:
the digits of a two-digit number are reversed, the new number is
than the original number
the sum of the digits of the original number is 11: .....
you will have:

.........both sides divide by

Replace with and plug it in

......the 10's digit
then, the units digit will be

and the original number is:
if the digits of a two-digit number are reversed, we will have a number

...so, the new number is
than the original number

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x+y=11
10x+y=10y+x+9
56 is the original number
new number is 65
check
65=56+9
6+5=11
ok
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