SOLUTION: I;m 46 and refreshing my algebra, help??? please
Jim has a total of 50 coins. Some are nickels and some are dimes. Altogether he has 4.15. How many dimes does he have and how
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Question 459936: I;m 46 and refreshing my algebra, help??? please
Jim has a total of 50 coins. Some are nickels and some are dimes. Altogether he has 4.15. How many dimes does he have and how many nickels?
Thanks
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
n+d=50 d=50-n
0.05n+0.1d=4.15
0.05n +0.1(50-n)=4.15
0.05n+5-0.1n=4.15
-0.05n=-0.85
n=17 nickles
50-17=33 dimes
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