SOLUTION: Urgent help please! Write the equation of the line that satisfies the given conditions. Express the final equation in standard form. Contains the point (-8, 6) and is perpendicu

Question 457951: Urgent help please! Write the equation of the line that satisfies the given conditions. Express the final equation in standard form.
Contains the point (-8, 6) and is perpendicular to the line 5x − y = 4

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Contains the point (-8, 6) and is perpendicular to the line 5x − y = 4
:
Find the slope of the given equation, put it in the slope/intercept form y-mx+b):
5x - y = 4
subtract 5x from both sides
-y = -5x + 4
y has to be positive, multiply both sides by -1
y = 5x - 4
slope (m1) = 5
The slope relationship of perpendicular lines: m1*m2 = -1
Find the slope of the perpendicular line (m2)
5*m2 = -1
m2 =
m2 = - .2
:
Find the equation of this line using the point/slope form: y - y1 - m(x-x1)
here we have m = -.2; x1=-8, y1=6
y - 6 = -.2(x - (-8))
y - 6 = -.2(x + 8)
Multiply inside the brackets by -.2
y - 6 = -.2x - 1.6
y = -.2x - 1.6x + 6
y = -.2x + 4.4
But they want this in the standard form
add.2x to both sides
.2x + y = 4.4
We want integer coefficients, multiply by 10
2x + 10y = 44 is the standard form
:
:
How about this, did each step make sense to you?

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