SOLUTION: Find the number of combinations. 10C6 12C8 14C10

Algebra.Com
Question 447492: Find the number of combinations.
10C6
12C8
14C10

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
nCx =
10C6 = 10!/6!*4! = 10*9*8*7/4*3*2 = 30*7 = 210
12C8 = 12!/8!*4! = 495
14C10 = 14!/10!*4! = 14*13*12*11/4*3*2 = 7*13*11 = 1001
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