SOLUTION: John is traveling to a meeting that is 29 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
A= 25mph
B= 37mph
C= 4
Algebra.Com
Question 444326: John is traveling to a meeting that is 29 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
A= 25mph
B= 37mph
C= 41mph
D= 49mph
E= 56mph
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
29/(1/2 hour)=58 mph..
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