SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles an hour and train B is traveling at 120 miles an hour. Train A passes a sts

Question 438469: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles an hour and train B is traveling at 120 miles an hour. Train A passes a ststion at 5:25 p.m. If train B passes the same station at 5:37 p.m., at what time will train B catch up to train A?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 100 miles an hour and train B is traveling at 120 miles an hour.
Train A passes a station at 5:25 p.m.
If train B passes the same station at 5:37 p.m., at what time will train B catch up to train A?
:
From the given information, we know that Train B is 12 min behind A at at 5:25 pm
therefore Train B is:
* 120 = 24 miles behind Train A at that time.
:
Let t = time required for Train B to catch Train A
:
Write a distance equation; dist = speed * time
:
Train B dist = Train A dist + 24 mi
120t = 100t + 24
120t - 100t = 24
20t = 24
t =
t = 1.2 hrs for B to catch A
:
Convert 1.2 hrs to hrs and minutes: 1 + .2(60) = 1 hr 12 min
:
Find the time from 5:25 pm:
5:25 + 1:12 = 6:37 pm, Train B catches Train A
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