SOLUTION: The general expression for consecutive multiples of 6 is 6N, 6(N+1), 6(N+2), etc. Find three consecutive multiples of 6 such that 4 times the first exeeds twice the third by 12.
Algebra.Com
Question 437357: The general expression for consecutive multiples of 6 is 6N, 6(N+1), 6(N+2), etc. Find three consecutive multiples of 6 such that 4 times the first exeeds twice the third by 12.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
4x6n=2x6(n+2)+12
24n=12n+24+12
24n=12n+36
12n=36
n=3
6n=18
6(n+1)=24
6(n+2)=30.
RELATED QUESTIONS
help!
The general expression for consecutive multiples of 6 is 6n, 6(n+1), 6(n+2) etc. (answered by checkley71)
The general expression for consecutive multiples of seven is 7N, 7(N+1), 7(N+2), etc.... (answered by ankor@dixie-net.com)
Assuming the general expression for multiples to be 3N, 3(n+1), 3(n+2) etc.
Find 4... (answered by robertb)
The general expression for consecutive multiples of 5 is 5N, 5(N+1), 5(N+2), and so on,... (answered by stanbon)
The sum of three consecutive multiples of 6 is 126.Find these three... (answered by Alan3354)
The general expression for consecutive multiples of seven 7n, 7(n+1), 7(n+2)where n is... (answered by ankor@dixie-net.com)
find 3 consecutive multiples of 3 such that 6 times the first is 48 greater than 4 times... (answered by checkley77)
multiples of 7 is 7N, 7(N+1), 7(N+2), and so on, where N is some unspecified integer.... (answered by ankor@dixie-net.com)
what is the product of three consecutive multiples of 5 if the middle number is... (answered by josgarithmetic)