SOLUTION: After opening the parachute, the descent of a parachutist follows a linear model. At 2:08 PM the height of the parachutist is 7000 feet. At 2:10 PM the height is 4600 feet.
a) Wri
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Question 433715: After opening the parachute, the descent of a parachutist follows a linear model. At 2:08 PM the height of the parachutist is 7000 feet. At 2:10 PM the height is 4600 feet.
a) Write a linear equation that gives the height of the parachutist in terms of time t. (Let t = 0 represent 2:08 PM and let t be measured in seconds.)
b) Use the equation in part (a) to find the time when the parachutist will reach the ground.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
You are given 2 points on the line:
(0,70.00) and (120,46.00)
Height is in hundreds of feet, and time is in seconds
The formula is:
answer ( h is in hundreds of feet )
check:
(120,46)
OK
When does
seconds
or, 5 minutes and 50 seconds
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