SOLUTION: Please help me solve this radical equation: √(y+10)=y-2

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Question 433003: Please help me solve this radical equation: √(y+10)=y-2
Answer by rwm(914)   (Show Source): You can put this solution on YOUR website!
square both sides
y+10=(y-2)^2
y+10 = y^2-4 y+4
-y^2+5 y+6 = 0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=49 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -1, 6. Here's your graph:

y=-1 y=6

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