Hi

 x^4-4x^3+4x-1 = 0    |If x=1 then 1-4+4-1 = 0 (x-1) a factor

dividing the above by (x-1)

x^3 - 3x^2 - 3x + 1    |If x= -1 then -1-3+3+1 = 0 (x+1) a factor

dividing the above by (x+1)

x^2 - 4x + 1









all the REAL zeros of the function:

 {-3.7321,-1, -.2679, 1 }

  

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