Hi

sum of its digits is 10

Let x and (10-x)represent the unit and tens digits of this certain two-digit number

Question states***   Note: [10*(10-x)+ x] the original number

 10*x + (10-x) = [10*(10-x)+ x] - 36

Solving for x

   9x + 10 = 100 - 9x - 36

     18x = 54

       x = 3, the units digit, 7 the ten digit, the Number is 73

CHECKING our Answer***

 37 = 73 - 36 

Answer by sudhanshu_kmr(1152)   (Show Source): You can put this solution on YOUR website!
 

let unit digit number is x , tenth digit is y...



x+y = 10  ..............(1)



original value of number is 10y + x 



after reversing it is 10x + y 



10y +x -( 10x +y ) = 36 



=> 9y - 9x = 36 



=> y - x = 4   (dividing by 4 both side)



now, add this equation to equation (1)



we find, 



2y = 14 



=> y = 7



and value of  x = 3 



so, original number is 7*10 + 3 = 73



after reversing it becomes   37 









   

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