# SOLUTION: Three consecutive even integers are such that the square of the first integer plus the square of the third integer is 136. Find the three integers.

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 Click here to see ALL problems on Evaluation Word Problems Question 402382: Three consecutive even integers are such that the square of the first integer plus the square of the third integer is 136. Find the three integers.Answer by checkley79(3056)   (Show Source): You can put this solution on YOUR website!Let x, x+2 & x=4 be the three integers. x^2+(x+4)^2=136 x^2+x^2+8x+16=136 2x^2+8x+16-136=0 2x^2+8x-120=0 2(x^2+4x-60)=0 2(x-6)(x+10)=0 x-6=0 x=6 ans. for the smallest integer. 6+4=10 ans. for the largest integer. Proof: 6^2+10^2=136 36+100=136 136=136