SOLUTION: Find four consecutive integers so that if the first is increased by 2, the second decreased by 2, the third multiplied by 2 and the fourth divided by 2, then the sum of the four re
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Question 357188: Find four consecutive integers so that if the first is increased by 2, the second decreased by 2, the third multiplied by 2 and the fourth divided by 2, then the sum of the four resulting numbers is 200.
Found 2 solutions by stanbon, neatmath:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find four consecutive integers so that if the first is increased by 2, the second decreased by 2, the third multiplied by 2 and the fourth divided by 2, then the sum of the four resulting numbers is 200.
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1st: x-1
2nd: x
3rd: x+1
4th: x+2
-------------------------
Equation:
x-1+2 + x-2 + 2(x+1) +(x+2)/2 = 200
----
x +1 + x - 2 + 2x+2 + (x+2)/2 = 200
4x +1 + (x+2)/2 = 200
8x+2 + x+2 = 400
9x + 4 = 400
9x = 396
x = 44
----
1st: 39
2nd: 40
3rd: 41
4th: 42
===============
Cheers,
Stan H.
Answer by neatmath(302) (Show Source): You can put this solution on YOUR website!
We know that four unknown consecutive integers would be in the form:
So, we then use this format to solve the problem, given:
Thus, the four consecutive integers we are looking for are:
43, 44, 45, and 46
I hope this helps!
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