SOLUTION: The perimeter of a rectangle is 64cm. Twice the width is 4cm more than the length. Find the dimensions. I don't understand how to do it. If you could show me some steps that'd

Question 356836: The perimeter of a rectangle is 64cm. Twice the width is 4cm more than the length. Find the dimensions.

I don't understand how to do it. If you could show me some steps that'd be great.
Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!

Let the length is x cm and width is y cm.
then perimeter 2(x+y) =64 cm
=> x+y = 64/2 = 32
=> x + y = 32 .............(1)

and according to question twice the width is 4cm more than length so,

2y = x + 4
=> 2y -x = 4 .............(2)
now we add these two equation to find the value of x and y.
3y = 36
=> y = 12
now put the value of y on any equation to find value of x ,
x +12 = 32
=> x = 32 -12 = 20

so length is 20cm and width is 12cm.
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