SOLUTION: The length of a rectangle is fixed at 21 cm. What widths will make the perimeter greater then 82 cm?

Question 324956: The length of a rectangle is fixed at 21 cm. What widths will make the perimeter greater then 82 cm?
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's have x represent the width of the shape.
Now we can set up the following inequality:
x+x+21+21>82
Combine like terms:
2x+42>82
Subtract 42 and divide by 2 to get:
x>20
There we go. Everything greater than 20 cm for the width is the answer.
Make sense?
RJ
www.math-unlock.com
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