SOLUTION: I have $6,000 to spend on dishes for the restaurant. There are two designs available, one for $20 and another for $45. How many of each can I buy? Please use the algebra substituti
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Question 284712: I have $6,000 to spend on dishes for the restaurant. There are two designs available, one for $20 and another for $45. How many of each can I buy? Please use the algebra substitution method where $20 is x and $45 is y. Thank you in advance.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
20x+45y=6000,
1
1
Not enough info
Two unknowns need two equations
There are 33 integer solutions.
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