SOLUTION: Two coins contain only dimes and quarters. The total value of the coins in the first bank is $15. In the second bank, there are 15 more dimes than in the first bank and half as man

Question 280872: Two coins contain only dimes and quarters. The total value of the coins in the first bank is $15. In the second bank, there are 15 more dimes than in the first bank and half as many quaRTERS. The total value of the second bank is $10.25. Find the number of dimes in the first bank.
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
Two coins contain only dimes and quarters. The total value of the coins in the first bank is $15. In the second bank, there are 15 more dimes than in the first bank and half as many quaRTERS. The total value of the second bank is $10.25. Find the number of dimes in the first bank.
Let x be the number of dimes in the first bank. Let y be the number of quarters in the first bank.
The number of dimes in the second bank then is x+15. The number for quarters in the second bank is .5*y.
So we have:
First Bank amount:
1.) .10*x + .25y = 15.00
Second Bank amount:
2.) .10*(x+15) + .25*(.5*y) = 10.25
Solve this system of equations for x.
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