SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 MPH and train B traveling at 60 MPH. train A passes a station at 9:20 PM. If tr

Question 254195: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 MPH and train B traveling at 60 MPH. train A passes a station at 9:20 PM. If train B passes the same station at 9:34 PM at what time will train B catch up to train A?
Found 2 solutions by checkley77, JimboP1977:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
d=40t for train A.
d=60(t-14/60) train B.
40t=60(t-14/60)
40t=60t-14
40t-60t=-14
-20t=-14
t=-14/-20=7/10=.7 hours.
.7*60=42 minutes.
9:20+:42=10:02 is the time they will meet.

Answer by JimboP1977(311) (Show Source): You can put this solution on YOUR website!
D=Distance
S=Speed
T=Time since leaving the station
D=40T (1)
D=60(T-(14/60))=D=60T-14 (2)
40T=60T-14
14=20T
7/10 = T
T=42 minutes.
So train B will catch train A at 10:02 PM.
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