SOLUTION:
ive tried to do this and i am stuck!!
" The second of two numbers is 3 less than twice the first. Their sum is 42. Find the numbers."
x = first number =
4x - 2 = se
Algebra.Com
Question 23863:
ive tried to do this and i am stuck!!
" The second of two numbers is 3 less than twice the first. Their sum is 42. Find the numbers."
x = first number =
4x - 2 = second number =
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
First number = x
Second number = 2x-3
Sum = 42
(x)+(2x-3)=42
3x-3+3=42+3
3x=45
x = 15 (first number)
2(15)-3=27(second number)
Hence, the two numbers are 15, and 27
Paul.
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