SOLUTION: The sum of 2 numbers is 108. If twice their difference is subtracted from the smaller, remainder is 9. Find the 2 numbers.
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Question 20779: The sum of 2 numbers is 108. If twice their difference is subtracted from the smaller, remainder is 9. Find the 2 numbers.
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
x+y=108
y=108-x
2x-2y=9
2x-2(108-x)=9
2x-216+x=9
3x-216=9
3x-216+216=9+216
3x=225
x=75, y=108-(75) /// y=33
Hence, the two numbers are 75 and 33.
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