SOLUTION: In electrical theory, Ohm's law states that I=V/ R, where I is the current in amperes, V is the electromotive force in volts, and R is the resistance in ohms. In a certain circuit

Question 206773This question is from textbook Algebra and Trigonometry with Analytic Geometry
: In electrical theory, Ohm's law states that I=V/ R, where I is the current in amperes, V is the electromotive force in volts, and R is the resistance in ohms. In a certain circuit V= 110 and R= 50. If V and R are to be changed by the same numerical amount, what change in them will cause I to double? This question is from textbook Algebra and Trigonometry with Analytic Geometry

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
In electrical theory, Ohm's law states that I=V/ R, where I is the current in amperes, V is the electromotive force in volts, and R is the resistance in ohms. In a certain circuit V= 110 and R= 50. If V and R are to be changed by the same numerical amount, what change in them will cause I to double?
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I = V/R
2I= (V+x)/(R+x)
2V/R = (V+x)/(R+x)
2*110/50 = (110+x)/(50+x)
220*(50+x) = 50*(110+x)
11000 + 220x = 5500+ 50x
5500 = -170x
x = -550/17
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