SOLUTION: A bacteria population starts at 2032 and decrease by 15% everyday.
Write a function representing the number of bacteria present each day.
After how many days will there be
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Question 198168: A bacteria population starts at 2032 and decrease by 15% everyday.
Write a function representing the number of bacteria present each day.
After how many days will there be fewer than 321 bacteria?
I need some help on this problem please.
Thank you in advance.
Found 2 solutions by ankor@dixie-net.com, arallie:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A bacteria population starts at 2032 and decrease by 15% everyday.
Write a function representing the number of bacteria present each day.
f(t) = 2032(1-.15)^t
f(t) = 2032*.85^t
:
After how many days will there be fewer than 321 bacteria?
2032*.85^t = 321
.85^t =
.85t = .1578
t*log(.85) = log(.1578)
-.07058t = -.80189
t
t = 11.36 days
We can say after 12 days there will be less than 321
:
Check solution on calc: enter 2032*.85^12 = 289 left which is less than 321
in 11 days: 2032*.85^11 = 340, more than 321
Answer by arallie(162) (Show Source): You can put this solution on YOUR website!
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