SOLUTION: If four out of five doctors prefer fast food, than at a convention of 455 doctors, how many probably ate fast food for lunch? Set up an equation and solve. thanks thanks

Question 178217: If four out of five doctors prefer fast food, than at a convention of 455 doctors, how many probably ate fast food for lunch? Set up an equation and solve.
thanks thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If four out of five doctors prefer fast food, than at a convention of 455 doctors, how many probably ate fast food for lunch? Set up an equation and solve.
--------------
Let x = # preferring fast food
-----
Equation:
x = (4/5)455 = 4*91 = 364
=============================
Cheers,
Stan H.
RELATED QUESTIONS
. Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by stanbon)

Fast Food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by nerdybill)

Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by checkley77)

Fast food. If four out of five doctors prefer fast food, then at a convention of 445... (answered by dabanfield)

If four out of five doctors prefer fast food, then at a convention of 445 doctors how... (answered by ewatrrr)

If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by checkley71,stanbon)

Please help me If four out of five doctors prefer fast food,then at a convention of 445... (answered by jim_thompson5910)

If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by stanbon)

If four out of five doctors prefer fast food, then at a convention of 445 doctors, how... (answered by ptaylor)