SOLUTION: A train leaves the station at 6p traveling west, going 80 miles per hour on a parallel track,a second train leaves the station three hours later traveling west at 100 miles and hou

Question 157769: A train leaves the station at 6p traveling west, going 80 miles per hour on a parallel track,a second train leaves the station three hours later traveling west at 100 miles and hour, at what time will the second train catch up with the first?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A train leaves the station at 6p traveling west, going 80 miles per hour on a parallel track,a second train leaves the station three hours later traveling west at 100 miles and hour, at what time will the second train catch up with the first?
.
You will have to apply the "distance formula"
d = rt
where
d is distance
r is rate or speed
t is time
.
Let x = time it will take for second train to catch up
.
For the trains to catch up, the distance traveled by both must be the same:
"distance traveled by 1st train" = "distance traveled by 2nd train"
80(t+3) = 100t
80t+240 = 100t
240 = 20t
12 hours = t
.
Conclusion:
12 hours after 6pm is 6am
Answer: 6 A.M.
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