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put this solution on YOUR website!soybean meal is 14% protein; cornmeal is 7% protein.how many pounds of each
should be mixed together in order to get 280lb mixture that is 12% protein?
:
how many pounds of cornmeal should be in the mixture?
:
Let x = amt of cornmeal required (7% protein):
:
how many pounds of soybean meal should be in the mixture?
:
(280-x) = amt of soymeal (14% protein) required
:
amt of protein equation:
.07x + .14(280-x) = .12(280)
:
.07x + 39.2 - .14x = 33.6
:
.07x - .14x = 33.6 - 39.2
;
-.07x = -5.6
x =
x = +80 lb of cornmeal required
:
280 - 80 = 200 lb of soymeal
:
:
Check solution:
.07(80) + .14(200) = .12(280)
5.6 + 28 = 33.6; confirms our solutions
