SOLUTION: Peaches were $7 a bushel and apples were $6 a bushel. Harry sold $346 worth and sold 29 more bushels of peaches than apples. How many bushels of each did he sell?

Question 1202283: Peaches were $7 a bushel and apples were $6 a bushel. Harry sold $346 worth and sold 29 more bushels of peaches than apples. How many bushels of each did he sell?
Found 3 solutions by ikleyn, greenestamps, josgarithmetic:
Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
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Peaches were $7 a bushel and apples were $6 a bushel.
Harry sold $346 worth and sold 29 more bushels of peaches than apples.
How many bushels of each did he sell?
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Let x be the number of bushels of apples. Then the number of bushels of peaches is (x+29). Write the total money equation 7(x+29) + 6x = 346. Simplify and find x 7x + 7*29 + 6x = 346 7x + 6x = 346 - 7*29 13x = 143 x = 143/13 = 11. ANSWER. 11 bushels of apples and (11+29) = 40 bushels of peaches. CHECK the total revenue 7*40 + 6*11 = 280 + 66 = 346 dollars. ! correct !

Solved.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!

While the problem was probably supposed to be solved using formal algebra, note that you can get good mental exercise by solving the problem informally, using logical reasoning and mental arithmetic.

The 29 "extra" bushels of peaches cost 29($7) = $203.
The remaining $346-$203 = $143 was the cost of equal numbers of bushes of peaches and apples.
The cost of one bushel each of peaches and apples was $13.
$143/$13 = 11, so the purchase after the "extra" bushels of peaches consisted of 11 bushels each of peaches and apples.
So the number of bushels of apples he sold was 11, and the number of bushels of peaches he sold was 11+29 = 40.

ANSWER: 11 bushels of apples and 40 bushels of peaches

CHECK: 11($6)+40($7) = $66+$280 = $346

Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!

PRICE BUSHELS qtn REVENUE Peaches 7 m+29 7(m+29) Apples 6 m 6m TOTAL 346

The revenue sum equation is , solve this for m.
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