Hi, I have the following math problem and wondering if possible can get some help. Thank you in advance.
A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% and the third contains 75%. He wants to use all three solutions to obtain a mixture of 64 liters containing 50% acid, using 33 times as much of the 75% solution as the 35% solution. How many liters of each solution should be used?
Another person did this before, used more than one variable, made a mistake that led to a WRONG answer. Now, another person has done it and still,
you're given directions that'll lead to a WRONG answer!
Here are the CORRECT formulation and the CORRECT answers. So, throw the following in the GARBAGE:
Let the amount of 35% solution to mix, be T
Then the amount of 75% solution is, 33T
Also, amount of 25% solution to mix is, 64 - (T + 33T) = 64 - 34T
We then get: .35T + .75(33T + .25(64 - 34T) = .5(64)
.35T + 24.75T + 16 - 8.5T = 32
16.6T = 32 - 16
16.6T = 16
Amount of 35% solution to mix, or
Amount of 75% solution to mix =
Amount of 25% solution to mix =
Accept NO OTHER answers!
I leave the check for you to do!
Tutor @IKLEYN! He should be IGNORED. He's an IDIOT and a racist who NEVER corrects the other people who make a VAST number of errors. He's
behind the times and wants to tell everyone how to do mathematics as if he knows it. He's just an OLD RACIST GOAT who wants to NITPICK and
CRITICIZE other people whose RACE he doesn't like! Do you realize that she chooses to pick fights with you and I? He needs to be IGNORED
and I hope he would just get LOST or disappear one of these days!