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Question 1169114: Twice the sum of the digits of a two-digit number is 14. The original number subtracted from the number formed when the digits are reversed is 27. What is the original number?
Found 3 solutions by ankor@dixie-net.com, greenestamps, MathTherapy: Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let the two digits be a & b
then
10a + b = the original number
:
Twice the sum of the digits of a two-digit number is 14.
2(a+b) = 14
simplify divide by 2
a + b = 7
The original number subtracted from the number formed when the digits are reversed is 27.
(10b + a) - (10a + b) = 27
10b - b + a - 10a = 27
9b - 9a = 27
simplify divide by 9
b - a = 3
:
Use elimination with these two equations
a + b = 7
-a + b = 3
---------------Addition eliminates a, find b
0 + 2b = 10
b = 10/2
b = 5
then
a + 5 = 7
a = 7 - 5
a = 2
:
What is the original number? 25
:
:
Confirm this in the statement:
"The original number subtracted from the number formed when the digits are reversed is 27."
52 - 25 = 27
Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website!
If twice the sum of the digits is 14, then the sum of the digits is 7.
If the original number subtracted from the number with the digits reversed is 27, then the difference between the digits is 27/9 = 3.
Sum of the two digits = 7 and difference of the two digits = 3 means the digits are 5 and 2.
ANSWER: 52
Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
Twice the sum of the digits of a two-digit number is 14. The original number subtracted from the number formed when the digits are reversed is 27. What is the original number?
Correct answer:
Since the original number, when SUBTRACTED from the reversed number, is 27, it's obvious that the reversed number will be LARGER than the original number.
Therefore, the original number CANNOT be 52.
Twice the sum of the 2 digits is 24, so sum of the 2 digits is 7.
Let tens digit be T
Then U (units digit) = 7 - T
Original number: 10T + U
Reversed number: 10U + T
We then get: 10U + T - (10T + U) = 27
10U + T - 10T - U = 27
9U - 9T = 27_____9(U - T) = 9(3)_____U - T = 3 ----- eq (i)
7 - T - T = 3 ------ Substituting 7 - T for U in eq (i)
- T - T = 3 - 7
- 2T = - 4
Tens digit or
Units digit: 7 - 2, or 5
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