SOLUTION: without graphing, determine the x and y-intercepts of the parabola
y=4(x-4)^2-36
please help thanks
Algebra.Com
Question 1135085: without graphing, determine the x and y-intercepts of the parabola
y=4(x-4)^2-36
please help thanks
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The
-intercepts are the points
where
is either of the two values of
whenever
is zero. So set
equal to zero and solve for
The
-intercept is the point
where
is the value of
when
is zero. So set
equal to zero and solve for 
John

My calculator said it, I believe it, that settles it

RELATED QUESTIONS
Please help me solve this problem:
The following equation defines a parabola. Without... (answered by nerdybill)
Please help me solve : Idetify the x and y-intercept of f(x). without graphing g(x),... (answered by ReadingBoosters)
Find the x and y intercepts of the parabola.
y = {{{-3(x + 4)^2 + 27}}}
x:___,___
(answered by lwsshak3)
please help me find the x intercepts of a parabola... (answered by scott8148)
1.The vertex is(4,-7),and the parabola opens upward.Determine the number of x-intercepts.
(answered by stanbon)
can you please help me determine how many x-intercepts the parabola has and wether its... (answered by mathsteacher)
A parabola has intercepts of x = -2, x = 3, and y = -4.
a. Write the intercept form of (answered by josgarithmetic,Edwin McCravy)
Without graphing, determine the vertex of the given parabola:
g(x) = x^2 + 16x - 3 (answered by rfer)
Please help me! Cannot figure this out. it says: without drawing the graph of the given... (answered by solver91311)