SOLUTION: A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. The distance S (in feet )of the ball from the ground, aft
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Question 1104536: A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. The distance S (in feet )of the ball from the ground, after t seconds is s=96+80t-16t^2.
a. How long does it take for the ball to reach its
highest point?
b. What is the maximum height the ball reaches?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A ball is thrown vertically upward from the top of a building 96 feet tall with an initial velocity of 80 feet per second. The distance S (in feet )of the ball from the ground, after t seconds is s=96+80t-16t^2.
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Use s(t) = -16t^2 + 80t + 96
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a. How long does it take for the ball to reach its
highest point?
The value of t at the vertex, t = -b/2a
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b. What is the maximum height the ball reaches?
The max is the vertex of the parabola.
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