SOLUTION: One number exceeds another by 3. One-third of their sum is 5 less than the smaller number. Find the numbers.
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Question 1064570: One number exceeds another by 3. One-third of their sum is 5 less than the smaller number. Find the numbers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
One number exceeds another by 3. One-third of their sum is 5 less than the smaller number. Find the numbers.
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x = y+3
(1/3)(x+y) = y-5
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Substitute::
(1/3)(y+3+y) = y-5
2y+3 = 3y-15
y = 18
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x = y+3 = 21
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Cheers,
Stan H.
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