SOLUTION: Use elimination to solve the problem. The sum of the digits of a two-digit number is 11. If the digits are reversed, the new number is 45 more than the original number. Find the

Question 1023270: Use elimination to solve the problem.
The sum of the digits of a two-digit number is 11. If the digits are reversed, the new number is 45 more than the original number. Find the number.
Found 2 solutions by ankor@dixie-net.com, MathTherapy:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a = original 10's digit
b = original units
;
The sum of the digits of a two-digit number is 11.
a + b = 11
If the digits are reversed, the new number is 45 more than the original number.
10a + b = 10b + a + 45
10a - a + b - 10b = 45
9a - 9b = 45
simplify divide by 9
a - b = 5
:
use elimination on these two equation
a + b = 11
a - b = 5
--------------adding eliminates b, find a
2a + 0 = 16
a = 16/2
a = 8
find b
a + b = 11
8 + b = 11
b = 11 - 8
b = 3
Find the number. 83
:
:
Check this, subtract;
83
38
---
45
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!

Use elimination to solve the problem.
The sum of the digits of a two-digit number is 11. If the digits are reversed, the new number is 45 more than the original number. Find the number.

Number:
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