SOLUTION: A newspaper carrier has $4.70 in change. He has seven more quarters than dimes but two times as many nickles as quarters. How many coins of each type does he have?
Algebra.Com
Question 997028: A newspaper carrier has $4.70 in change. He has seven more quarters than dimes but two times as many nickles as quarters. How many coins of each type does he have?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
n = number of nickels
d = number of dimes
q = number of quarters
5n + 10d + 25q = 470
q = d + 7
n = 2q
Write everything in terms of d.
5(2(d+7)) + 10d + 25(d + 7) = 470
10d + 70 + 10d + 25d + 175 = 470
45d = 225
d = 5
There are 24 nickels, 5 dimes, and 12 quarters.
RELATED QUESTIONS
a newspaper carrier has $3.35 in change. He has seven more quarters than dimes but two... (answered by LinnW)
a newspaper carrier has 12.30 in change. He has two more quarters than dimes but three... (answered by ewatrrr)
a newspaper carrier has $4.90 in change. He has five more quarters than dimes but two... (answered by josgarithmetic,algebrahouse.com,ikleyn)
a newspaper carrier has $6.30 in change. he has three times more quarters than dimes but (answered by stanbon)
a newspaper carrier has $4.25 in change. He has seven more quarters than dimes but four... (answered by mananth)
newspaper carrier $6.85 in change 3 more quarters than dimes but four times as many... (answered by josgarithmetic)
A newspaper carrier has $7.30 in change. He has two more quarters than dimes but three... (answered by TimothyLamb)
A newspaper carrier has $2.20 in change. He has two more quarters than dimes but five... (answered by ewatrrr)
A newspaper carrier has $4.10 in change. He has four more quarters than dimes but two... (answered by ikleyn)