SOLUTION: Mandy has 2980 pesos in 1 peso, 5 peso, and 10 peso coins. If she has twice as many 5 peso coins as 1 peso coins and fifty more 10 peso coins than 5 peso coins, how many coins of e

Question 993627: Mandy has 2980 pesos in 1 peso, 5 peso, and 10 peso coins. If she has twice as many 5 peso coins as 1 peso coins and fifty more 10 peso coins than 5 peso coins, how many coins of each type does she have?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
p = number of 1 peso coins
n = number of 5 peso coins
d = number of 10 peso coins

p + 5n + 10d = 2980
n = 2p
d = n + 50

Write everything in terms of p.

p + 5(2p) + 10(2p + 50) = 2980
p + 10p + 20p + 500 = 2980
31p = 2480
p = 80

Mandy has 80 1-peso coins, 160 5-peso coins, and 210 10-peso coins.
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