SOLUTION: Frank had a bagful of coins totaling $13.00. He said, "Guess how many of each coin type I have if six less quarters than dimes and ten more than seven times as many nickles than di

Question 992760: Frank had a bagful of coins totaling $13.00. He said, "Guess how many of each coin type I have if six less quarters than dimes and ten more than seven times as many nickles than dimes?" (Solve with only using one variable)
When I did the problem I got frank has 14 quarters, 20 nickles, and 150 dimes, which I don't think is right. Please help.
Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!

Let D = the number of dimes. Then
The value of the dimes = 0.10D

I have...six less quarters than dimes

The number of the quarters = D-6
Value of quarters = 0.25(D-6)

and ten more than seven times as many nickles than dimes

number of nickels = 7D+10
Value of nickels = 0.05(7D+10)

coins totaling $13.00

Value of dimes + Value of quarters + value of nickels = 13.00
       D       +      0.25(D-6)    +    0.05(7D+10)   = 13.00

Multiply through by 100 to clear decimals:

  100D + 25(D-6) + 5(7D+10) = 1300

100D + 25D - 150 + 37D + 50 = 1300 

That works out to 8 3/4 dimes, so something is wrong 

Edwin

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