SOLUTION: Each coin in the collection of 56 coins is neither silver or gold. The number of silver coins is 8 more than 3 times the number of gold coins. Find the number of gold coins.

Question 991024: Each coin in the collection of 56 coins is neither silver or gold. The number of silver coins is 8 more than 3 times the number of gold coins. Find the number of gold coins.
Answer by colliefan(242) (Show Source): You can put this solution on YOUR website!
The number of gold coins plus silver coins equals 56.
Let's call the number of gold coins x.
Since the number of silver is 8 more than 3 times the number of gold, we could write it as 8+3X or 3x+8.
Putting these ways of representing gold and silver coins into the first equation gives:
gold + silver =56
x + (3x+8) = 56
x +3x +8 =56
4x +8 = 56
4x+8-8=56-8
4x+0=48
4x=48
4x/4=48/4
x=12
So the number of gold coins is 12.
Silver must be 3(12)+8 = 36+8 = 44.
Plug these number in to check your work.
gold+silver=56
12+44 does equal 56.
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