SOLUTION: Mary has $6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and eighty-seven more nickels than dimes, how many coins of each type does she have?

Question 990746: Mary has $6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and eighty-seven more nickels than dimes, how many coins of each type does she have?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = number of nickels
Let = number of dimes
Let = number of quarters
----------------------------
(1) ( in cents )
(2)
(3)
------------------
There are 3 equations and 3 unknowns, so it's solvable
(2)
Substitute (2) and (3) into (1)
(1)
(1)
Multiply both sids by
(1)
(1)
(1)
and
(2)
(2)
(2)
and
(3)
(3)
(3)
There are 93 nickels
There are 6 dimes
There are 3 quarters
-------------------
Check:
(1)
(1)
(1)
(1)
OK
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