SOLUTION: Michael has 60 coins consisting of nickels and dime. Their total value was $5.00. How many of each does he have
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Question 990002: Michael has 60 coins consisting of nickels and dime. Their total value was $5.00. How many of each does he have
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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N=nickels; D=dimes
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N+D=60
D=60-N
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$0.05N+$0.10D=$5.00
$0.05N+$0.10(60-N)=$5.00
$0.05N+$6.00-$0.10N=$5.00
-$0.05N=-$1.00
N=20
ANSWER 1: He has 20 nickels.
D=60-N=60-20=40
ANSWER 2: He has 40 dimes.
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CHECK:
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$0.05N+$0.10D=$5.00
$0.05(20)+$0.10(40)=$5.00
$1.00+$4.00=$5.00
$5.00=$5.00
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