SOLUTION: Norman has a dollar consisting of nickels, dimes and quarters. He has 2 ore dimes tan quarters and 6 more nickels than dimes. How many coins of each type does he have?

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Question 989905: Norman has a dollar consisting of nickels, dimes and quarters. He has 2 ore dimes tan quarters and 6 more nickels than dimes. How many coins of each type does he have?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
n, d, q for nickels, dimes, quarters.



What to do, as a plan:
Simplify the money dollar equation to have whole number coefficients. Use the two coin relationship equations to make substitutions for d in the simplified money one dollar equation.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Norman has a dollar consisting of nickels, dimes and quarters. He has 2 ore dimes tan quarters and 6 more nickels than dimes. How many coins of each type does he have? 
Let number of quarters be Q

Then number of dimes = Q + 2, and number of nickels = Q + 2 + 6, or Q + 8

The value equation, thus formed is: .25Q + .1(Q + 2) + .05(Q + 8) = 1

.25Q + .1Q + .2 + .05Q + .4 = 1

.25Q - .1Q + .05Q + .2 + .4 = 1

.4Q + .6 = 1

.4Q = 1 - .6

.4Q = .4

Q, or number of quarters = , or 

You should be able to find the number of dimes and nickels. 

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