SOLUTION: Michael has $2.08, consisting of pennies, nickels, and dimes. If he has one-half as many dimes as nickels and three times as many pennies as nickels, how many of each coin does he

Question 988908: Michael has $2.08, consisting of pennies, nickels, and dimes. If he has one-half as many dimes as nickels and three times as many pennies as nickels, how many of each coin does he have?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
p = number of pennies
n = number of nickels
d = number of dimes

p + 5n + 10d = 208
d = n/2
p = 3n

Write everything in terms of n.

3n + 5n + 10(n/2) = 208
13n = 208
n = 16

Michael has 48 pennies, 16 nickels, and 8 dimes.
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