SOLUTION: A newspaper carrier has $7.10 in change. He has ten more quarters than dimes but two times as many nickels as quarters. How many coins of each type does he have? This is what I

Question 984043: A newspaper carrier has $7.10 in change. He has ten more quarters than dimes but two times as many nickels as quarters. How many coins of each type does he have?
This is what I got so far: x + 3 2(x+3)

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = number of nickels
Let = number of dimes
Let = number of quarters
------------------------------
(1) ( in cents )
(2)
(3)
--------------------
You have 3 equations and 3 unknowns,
so it's solvable
(2)
Substitute (2) and (3) into (1)
(1)
(1)
(1)
(1)
and
(3)
(3)
(3)
and
(2)
(2)
(2)
--------------------
He has:
36 nickels
8 dimes
18 quarters
------------------
check:
(1)
(1)
(1)
(1)
OK
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