SOLUTION: A man has $10.40 in change consisting of 3 times as many quarters as nickels. how many quarters and nickels does he have?

Question 982195: A man has $10.40 in change consisting of 3 times as many quarters as nickels. how many quarters and nickels does he have?
Found 2 solutions by mananth, macston:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
nickel -x
quarters be y
y=3x
value and number of coins
5x+25y=1040
substitute y
5x+25(3x)=1040
80x=1040
x=1040/80
x=13
13 nickels and (13*3) =39 quarters

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
N=nickels; Q=quarters=3N
.
$0.05N+$0.25Q=$10.40
$0.05N+$0.25(3N)=$10.40
$0.05N+$0.75N=$10.40
$0.80N=$10.40
N=13 ANSWER 1:There are 13 nickels.
Q=3N=3(13)=39 ANSWER 2: here are 39 quarters.
.
CHECK:
$0.05N+$0.25Q=$10.40
$0.05(13)+$0.25(39)=$10.40
$0.65+$9.75=$10.40
$10.40=$10.40
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